3p^2-13pq^1+4q^2=0

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Solution for 3p^2-13pq^1+4q^2=0 equation:


Simplifying
3p2 + -13pq + 4q2 = 0

Reorder the terms:
-13pq + 3p2 + 4q2 = 0

Solving
-13pq + 3p2 + 4q2 = 0

Solving for variable 'p'.

Factor a trinomial.
(p + -4q)(3p + -1q) = 0

Subproblem 1

Set the factor '(p + -4q)' equal to zero and attempt to solve: Simplifying p + -4q = 0 Solving p + -4q = 0 Move all terms containing p to the left, all other terms to the right. Add '4q' to each side of the equation. p + -4q + 4q = 0 + 4q Combine like terms: -4q + 4q = 0 p + 0 = 0 + 4q p = 0 + 4q Remove the zero: p = 4q Simplifying p = 4q

Subproblem 2

Set the factor '(3p + -1q)' equal to zero and attempt to solve: Simplifying 3p + -1q = 0 Solving 3p + -1q = 0 Move all terms containing p to the left, all other terms to the right. Add 'q' to each side of the equation. 3p + -1q + q = 0 + q Combine like terms: -1q + q = 0 3p + 0 = 0 + q 3p = 0 + q Remove the zero: 3p = q Divide each side by '3'. p = 0.3333333333q Simplifying p = 0.3333333333q

Solution

p = {4q, 0.3333333333q}

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